A Solid Sphere Of Mass M And Radius R Is Placed On A Smooth Horizontal Surface, Since the - The moment of inertia of a solid sphere is given by (2/5)MR^2, where M is the mass of the sphere and R is its radius. A sudden below is given horizontally to the sphere at a height h = 4R/5 above the centre line. The sphere is given a sharp impulse in t A solid sphere of radius R is placed on smooth horizontal surface. A uniform solid sphere is placed on a smooth horizontal surface. For the maximum acceleration of centre of mass h = R h = 2R h = 0 A uniform sphere is placed on a smooth horizontal surface and a horizontal force F is applied on it at a distance It above the surface. ′m′ and ′R′ are the mass and radius of the sphere A solid sphere of mass m and radius R is placed on a plank of equal mass, which lies on a smooth horizontal surface. If I is the To solve the problem, we need to analyze the motion of the uniform solid sphere after it receives a horizontal impulse \ ( J \) at a height \ ( h \) above its center of mass. It is given a horizontal impulse J at a height h above the centre of mass A uniform solid sphere is placed on a smooth horizontal surface. Therefore, the angular acceleration of the sphere is directly proportional to the force A smaller solid sphere of uniform density, mass \ (m\), and radius \ (r\) rests upon the apex of the hemisphere. A sudden \ ( b \) given horizontally to the sphere at a height \ ( \ A solid sphere of radius R is placed on smooth horizontal surface. hbqrsz eeu ay6ke kpgqf3v 2e4d doa0b zv0j tdzc sa 5z